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Index: Mathematics of the Discrete Fourier Transform (DFT), with Audio Applications -- Second Edition
Mathematics of the Discrete Fourier Transform (DFT), with Audio Applications -- Second Edition
Fourier Theorems for the DFT
Alias Operator
Fourier Theorems
Click for https://ccrma.stanford.edu/~jos/mdft/Orthogonality.html
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A sinusoid is any function of the form A sin(ω t+φ), where t is the independent variable, and A, ω, φ are fixed parameters of the sinusoid called the amplitude, (radian) frequency, and phase, respectively. Sinusoidal motion is produced by any 'pure' vibration, such as that of an ideal tuning fork or mass-spring system. — Click for https://ccrma.stanford.edu/~jos/mdft/Sinusoids.html
The Discrete Fourier Transform (DFT) computes a discrete-frequency spectrum from a discrete-time signal of finite length. — Click for https://ccrma.stanford.edu/~jos/mdft/
A signal is typically a real-valued function of time. A discrete-time signal is typically a real-valued function of discrete time, and is therefore a time-ordered sequence of real numbers. — Click for http://ccrma.stanford.edu/~jos/filters/Definition_Signal.html
Click for http://archives.math.utk.edu/visual.calculus/0/functions.14/index.html
Click for http://archives.math.utk.edu/visual.calculus/0/functions.14/index.html
Click for http://archives.math.utk.edu/visual.calculus/0/functions.14/index.html
The Fourier theorems establish important, elementary time-frequency relationships. The theorems are largely the same whether stated for the case of the Fourier Transform (FT), Discrete Fourier Transform (DFT), Discrete Time Fourier Transform (DTFT), or Fourier Series (FS). — Click for https://ccrma.stanford.edu/~jos/mdft/Fourier_Theorems.html
Click for http://archives.math.utk.edu/visual.calculus/0/functions.14/index.html
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Index: Mathematics of the Discrete Fourier Transform (DFT), with Audio Applications -- Second Edition
Mathematics of the Discrete Fourier Transform (DFT), with Audio Applications -- Second Edition
Note that every finite odd function must satisfy
.7.12 Moreover, for any odd with
even, we also have since
; that is, and index
the same point when is even (since all indexing in is modulo ).
Theorem: Every function can be
uniquely
decomposed into a sum of its even part
and odd part , where
Proof: In the above definitions, is even and is odd by construction.
Summing, we have
To show uniqueness, let denote some other
even-odd decomposition. Then , and .
Theorem: The product of even functions is even, the product of odd functions
is even, and the product of an even times an odd function is odd.
Proof: Readily shown.
Since even times even is even, odd times odd is even, and even times odd is
odd, we can think of even as and odd as :
for any even signal and odd signal in . In
terms of inner products (§5.9), we may say that the even part
of every real signal is orthogonal to its odd part:
Check Your Understanding
Exercise 1Multiple Choice
Any function x(t) can be decomposed into even and odd parts. What is the even part xe(t)?
[x(t) + x(-t)] / 2
[x(t) - x(-t)] / 2
x(t) + x(-t)
x(t) · x(-t)
An even function satisfies f(-t) = f(t)
Adding x(t) and x(-t) cancels the odd part
Exercise 2Multiple Choice
For N = 4, the sequence x = [0, 1, 2, 1] has the property that x[−n] = x[N−n]. What are the even and odd parts of x?
xe = [0, 1, 2, 1], xo = [0, 0, 0, 0]
xe = [0, 0, 0, 0], xo = [0, 1, 2, 1]
xe = [0, 1, 2, 1], xo = [0, 1, 2, 1]
xe = [0, 0.5, 1, 0.5], xo = [0, 0.5, 1, 0.5]
Compute x[−n] mod 4: x[0]=0, x[−1]=x[3]=1, x[−2]=x[2]=2, x[−3]=x[1]=1.
Even part = (x[n] + x[−n])/2. If x[n] = x[−n], the odd part vanishes.
Exercise 3Multiple Choice
For N = 4, the sequence x = [0, 1, 0, −1]. Compute its even part xe and odd part xo (indices modulo 4).
xe = [0, 0.5, 0, −0.5], xo = [0, 0.5, 0, −0.5]
xe = [0, 1, 0, −1], xo = [0, 0, 0, 0]
xe = [0, 0, 0, 0], xo = [0, 1, 0, −1]
xe = [0, −1, 0, 1], xo = [0, 1, 0, −1]
Compute x[−n] mod 4: position 1 maps to position 3, and vice versa.
If x[−n] = −x[n] for all n, the sequence is purely odd and its even part is zero.
Exercise 4Multiple Choice
For N = 4, find the even part of x = [0, 1, 2, 3] (indices modulo 4).
[0, 2, 2, 2]
[0, 1, 2, 3]
[0, 2, 4, 6]
[0, −1, 0, 1]
x[−n] mod 4: reverse positions 1 and 3, keep 0 and 2 fixed.
Even part = (x[n] + x[−n])/2 element-by-element.
Exercise 5Multiple Choice
For N = 4 (indexing modulo N), what is the odd part xo of the sequence x = [0, 1, 2, 3]?
[0, −1, 0, 1]
[0, 1, 0, −1]
[0, 2, 2, 2]
[0, 1, 2, 3]
xo[n] = (x[n] − x[−n])/2, where −n is taken modulo N.
Reverse [0,1,2,3] modulo 4 to get [0,3,2,1], then subtract and halve.